A=(x^2+5)

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Solution for A=(x^2+5) equation: 



=(A^2+5)

We move all terms to the left:

-((A^2+5))=0



We calculate terms in parentheses: -((A^2+5)), so:

(A^2+5)

We get rid of parentheses

A^2+5

Back to the equation:

-(A^2+5)



We get rid of parentheses

-A^2-5=0

We add all the numbers together, and all the variables

-1A^2-5=0

a = -1; b = 0; c = -5;
Δ = b2-4ac
Δ = 02-4·(-1)·(-5)
Δ = -20
Delta is less than zero, so there is no solution for the equation

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